Timeline for Is there a concept of uniform Hausdorff dimension?
Current License: CC BY-SA 3.0
4 events
when toggle format | what | by | license | comment | |
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Sep 6, 2016 at 7:37 | vote | accept | quarague | ||
Sep 6, 2016 at 7:01 | comment | added | N Unnikrishnan | Well, the unit interval $I$ is not open as a subset of $\mathbb{R}^2$, so it doesn't invalidate the "uniform Hausdorff dimension" of the disjoint union of $I$ and $D$ being 2 according to your definition. | |
Sep 5, 2016 at 13:55 | answer | added | user98074 | timeline score: 5 | |
Sep 5, 2016 at 12:18 | history | asked | quarague | CC BY-SA 3.0 |