Timeline for Density measure on $\mathbb{N}^2$
Current License: CC BY-SA 3.0
10 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Sep 5, 2016 at 11:14 | vote | accept | Dominic van der Zypen | ||
| Sep 5, 2016 at 10:42 | answer | added | Goldstern | timeline score: 4 | |
| Sep 5, 2016 at 9:52 | comment | added | Wojowu | @PietroMajer I think you have a point; I was thinking about $\lim$ instead of $\limsup$. | |
| Sep 5, 2016 at 9:39 | comment | added | Pietro Majer | I'd try the limit superior as $n\to\infty,m\to\infty$ of means on rectangles {$1,\dots,n$}$\times${$1,\dots,m$} instead of squares. | |
| Sep 5, 2016 at 9:29 | comment | added | Pietro Majer | I think Wojowu's would satisfy 1 and 3 but not 2. Consider $B=A^c$, with upper density 1 and lower density 0... | |
| Sep 5, 2016 at 9:04 | history | edited | Dominic van der Zypen | CC BY-SA 3.0 |
added 56 characters in body
|
| Sep 5, 2016 at 9:03 | comment | added | Dominic van der Zypen | Oh - possibly, have to think about it... If you can give a short argument, please write an answer? | |
| Sep 5, 2016 at 9:03 | comment | added | Wojowu | Wouldn't $\limsup_{n\rightarrow\infty}|A\cap\{1,\dots,n\}^2|/n^2$ do? | |
| Sep 5, 2016 at 9:02 | history | edited | Dominic van der Zypen | CC BY-SA 3.0 |
added 226 characters in body
|
| Sep 5, 2016 at 8:56 | history | asked | Dominic van der Zypen | CC BY-SA 3.0 |