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Timeline for (Path) connected set of matrices?

Current License: CC BY-SA 2.5

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May 16, 2010 at 12:48 vote accept Portland
May 17, 2010 at 1:35
May 16, 2010 at 12:32 history edited Xandi Tuni CC BY-SA 2.5
Took back a false claim.
May 16, 2010 at 12:11 comment added Xandi Tuni Oops, my fault. I will look if I can fix that.
May 16, 2010 at 12:02 comment added Sergei Ivanov No, the square of Jordan type (4) is (2,2).
May 16, 2010 at 11:57 comment added Xandi Tuni Jordan type $(3,3)$ has square $(2,1,2,1) = (2,2,1,1)$ and Jordan type $(4,2)$ has square $(3,1,1,1)$. Is that not so?
May 16, 2010 at 11:45 comment added Sergei Ivanov How do you connect Jordan type (3,3) to (4,2)? They have the same square.
May 16, 2010 at 10:55 history answered Xandi Tuni CC BY-SA 2.5