Timeline for Pullback along Frobenius morphism
Current License: CC BY-SA 3.0
7 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Feb 11, 2020 at 20:37 | comment | added | MAS | @SashaP, what does mean by the sentence "the group $\mathbb{Z}/p\mathbb{Z}$ acts by cyclic permutation on $\mathcal{M}^{\otimes p}$" ? The group $\mathbb{Z}/p \mathbb{Z}:=\{\bar 0, \bar 1, \cdots, \overline{p-1} \}$. A generator is $\bar 1$. Then why get $\sigma$ ? Is $\sigma$ a permutations on the elements of $\mathbb{Z}/p \mathbb{Z}$ ? Can you please explain the first line ? | |
| Oct 23, 2016 at 10:51 | vote | accept | Martin Brandenburg | ||
| Oct 23, 2016 at 10:51 | comment | added | Martin Brandenburg | Oh, you are right. I forgot that. | |
| Oct 21, 2016 at 17:27 | comment | added | SashaP | @MartinBrandenburg Sure, but I thought you are asking about locally free sheaf which is automatically flat, aren't you? | |
| Oct 21, 2016 at 13:55 | comment | added | Martin Brandenburg | Interesting, but this only holds when $M$ is flat. (See the comments before Lemma 6.9, and the proof.) | |
| Aug 30, 2016 at 15:57 | history | edited | SashaP | CC BY-SA 3.0 |
added 74 characters in body
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| Aug 30, 2016 at 14:51 | history | answered | SashaP | CC BY-SA 3.0 |