Timeline for Is it possible to classify finite dimensional vector bundles in terms of Fredholm operators?
Current License: CC BY-SA 3.0
8 events
| when toggle format | what | by | license | comment | |
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| Aug 19, 2019 at 13:57 | comment | added | Thomas Rot | @JesseC.McKeown: Just a ping | |
| Aug 19, 2019 at 13:57 | answer | added | Thomas Rot | timeline score: 4 | |
| Apr 13, 2017 at 12:58 | history | edited | CommunityBot |
replaced http://mathoverflow.net/ with https://mathoverflow.net/
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| Aug 31, 2016 at 1:33 | comment | added | Jesse C. McKeown | Being the Jesse mentioned, I'm also keen to understand what my spaces actually are, and well open to the possibility that they're not BU(n)s. | |
| Aug 29, 2016 at 7:47 | comment | added | Thomas Rot | Let $\mathcal{K}_k^l$ be the space of index $k$ Fredholm operators whose kernel is $l$ dimensional. There is a fiber sequence $GL(\mathbb{H})\rightarrow \mathcal{K}_k^l\rightarrow BU(l)\times BU(k-l)$ where the right map is mapping an operator to the kernel times the cokernel. It follows that $\mathcal{K}_k^l$ is homotopy equivalent to $BU(l)\times BU(k-l)$. I do not now what happens when one takes the union over $l\leq l_0$. | |
| Aug 29, 2016 at 6:53 | history | edited | Gregory Arone | CC BY-SA 3.0 |
added 290 characters in body
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| Aug 28, 2016 at 16:54 | history | edited | Gregory Arone | CC BY-SA 3.0 |
edited body
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| Aug 28, 2016 at 16:45 | history | asked | Gregory Arone | CC BY-SA 3.0 |