Timeline for If $\mathcal{A} \equiv \mathcal{B}$ and $\mathcal{A} \not \cong \mathcal{B}$, is it possible that $\mathcal{A}$ and $\mathcal{B}$ are bi-embeddable?
Current License: CC BY-SA 3.0
4 events
| when toggle format | what | by | license | comment | |
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| Aug 25, 2016 at 20:56 | history | edited | Noah Schweber | CC BY-SA 3.0 |
added 429 characters in body
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| Aug 25, 2016 at 20:52 | vote | accept | Dino Rossegger | ||
| Aug 25, 2016 at 20:55 | |||||
| Aug 25, 2016 at 16:57 | history | edited | Noah Schweber | CC BY-SA 3.0 |
added 164 characters in body
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| Aug 25, 2016 at 16:42 | history | answered | Noah Schweber | CC BY-SA 3.0 |