Timeline for Is cohomology of groups all about $H^{i}: -2\leq i\leq 2$?
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4 events
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| Aug 24, 2016 at 6:42 | comment | added | user37663 | Thanks for the clarification. I just need some time to understand. I will try one more time... :) | |
| Aug 23, 2016 at 21:18 | comment | added | Joe Silverman | @PraphullaKoushik Sorry for the ambiguity, it's the usual Brauer group $\text{Br}(K)=H^2(G_{\overline K}/K,\overline K^*)$. One gets a pairing from on $III(E/K)$ that takes values in $\text{Br}(K)$. Hmmm...,no actually, that's not quite right, either, one gets values in $\mathbb Q/\mathbb Z$ by getting an element of the local Brauer groups and adding up their invariants. Anyway, it's not an elliptic curve Brauer group. | |
| Aug 23, 2016 at 19:08 | comment | added | user37663 | I am happy that my question has got your interest.. I am not familiar with elliptic curves brauer groups... I will come back and rtry to understand this once I am ready... Thank you | |
| Aug 23, 2016 at 17:22 | history | answered | Joe Silverman | CC BY-SA 3.0 |