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Jun 15, 2020 at 7:27 history edited CommunityBot
Commonmark migration
Mar 28, 2020 at 23:03 comment added goblin GONE @Thorsten, the idea is to regard $X^*$ as a sheaf, and hence a functor in its own right. Unpacking the definitions, we find that a natural transformation $f : X^* \rightarrow Y^*$ is basically a function $f : X^\mathbb{N} \rightarrow Y^\mathbb{N}$ with the property that for all $\alpha,\beta \in X^\mathbb{N}$, we have $$(\alpha \restriction n) = (\beta \restriction n) \rightarrow (f(\alpha) \restriction n) = (f(\beta) \restriction n).$$
Mar 25, 2019 at 21:16 comment added LSpice $\DeclareMathOperator\Hom{Hom}$@Thorsten, I think I must misunderstand your [comment](mathoverflow.net/questions/247891/…). What does "all pairs of sets $(X, Y)$ have the same hom-set" mean? Surely $\Hom_{\mathbf{Set}}(\emptyset, {*}) \ne \Hom_{\mathbf{Set}}({*}, \emptyset)$?
Aug 7, 2017 at 13:27 comment added Thorsten And in programming, stateful functions are modelled using the Kleisli-Category of the state monad.
Aug 7, 2017 at 13:25 comment added Thorsten It is unclear what you mean by "natural transform $X*\to Y^*$". Do you mean "natural transformations between the functors from the functor $X\mapsto X^*$ to $Y\mapsto Y^*$? If yes, note that all pairs of sets $(X,Y)$ have the same hom-set. If no, what's a natural transform?
Aug 20, 2016 at 18:51 comment added Musa Al-hassy This seems to be essentially the theory of polymorphic list operations ---as in functional programming--- and there's a host of categorical results there. As for the internal logic, in computer science, lists are used as naive representations for relations and so looking in that direction may be fruitful.
Aug 20, 2016 at 7:53 comment added მამუკა ჯიბლაძე As you admit yourself, the question is rather vague, so I don't know how to answer. Still, in case it helps to clarify something - your $\mathbf{Set}^*$ seems to be isomorphic to the coKleisli category of the comonad structure on $\_^*$, with $\varepsilon(x_1,...,x_n)=x_n$ and $\delta(x_1,...,x_n)=((x_1),...,(x_1,...,x_n))$.
Aug 20, 2016 at 7:11 history asked goblin GONE CC BY-SA 3.0