Timeline for algebraic version and polar decomposition
Current License: CC BY-SA 3.0
6 events
| when toggle format | what | by | license | comment | |
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| Aug 22, 2016 at 21:32 | answer | added | Ruy | timeline score: 2 | |
| S Aug 19, 2016 at 20:51 | history | suggested | LSpice | CC BY-SA 3.0 |
Fixed quantification ($w$ depends on $b$), and tried to clean up language
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| Aug 19, 2016 at 20:32 | review | Suggested edits | |||
| S Aug 19, 2016 at 20:51 | |||||
| Aug 19, 2016 at 20:08 | comment | added | Branimir Ćaćić | To get the modulus $|b| = \sqrt{b^\ast b}$ of $b$, you need to be able to take positive square roots of positive definite elements, presumably through some sort of functional calculus on your $\ast$-algebra more general than the polynomial functional calculus. Setting up such a functional calculus, however, is precisely where a topology on your $\ast$-algebra will likely enter the picture. | |
| Aug 19, 2016 at 19:51 | history | edited | YCor |
edited tags
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| Aug 19, 2016 at 19:50 | history | asked | Wagner De Oliveira Cortes | CC BY-SA 3.0 |