Skip to main content

Timeline for Global sections of G/B and G/P

Current License: CC BY-SA 3.0

9 events
when toggle format what by license comment
Aug 13, 2016 at 10:33 vote accept Pitor
Aug 13, 2016 at 10:31 comment added Pitor No, I will assume P to be a proper parabolic subgroup of G.
Aug 12, 2016 at 22:17 comment added Jim Humphreys @Pitor: Do you allow $P$ to equal $G$? That is technically possible for a parabolic subgroup.
Aug 12, 2016 at 13:10 answer added Allen Knutson timeline score: 1
Aug 12, 2016 at 11:19 comment added Jason Starr The morphism from $G/B$ to $G/P$ is rational. The derived pushforward of the structure sheaf of $G/B$ is naturally equivalent to the (complex supported in degree $0$ of the) structure sheaf of $G/P$. Combine this with the projection formula.
Aug 12, 2016 at 7:08 comment added Sasha Use the projection formula.
Aug 12, 2016 at 7:05 comment added Wilberd van der Kallen The fiber is $P/B$.
Aug 12, 2016 at 5:00 review First posts
Aug 12, 2016 at 5:40
Aug 12, 2016 at 4:55 history asked Pitor CC BY-SA 3.0