Timeline for Invariant complementary sets modulo $p$
Current License: CC BY-SA 3.0
5 events
when toggle format | what | by | license | comment | |
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Aug 12, 2016 at 20:48 | comment | added | user44191 | $k \equiv 1 (mod n)$ didn't affect the proof; however, it would be necessary for any such partition, as the $s$-cosets must all have size $n$. Therefore, stating it is unnecessary. The only assumptions I really used about $p, k, n$ are that $1 < n, 1 < k < p, p$ prime. | |
Aug 12, 2016 at 19:05 | comment | added | Sávio | I mean, $2 \le k \le p-1$ | |
Aug 12, 2016 at 4:14 | comment | added | Sávio | Indeed, the hypothesis $k \equiv 1 \pmod n$ is useless. You just used $1 \le k \le q-1$, right? Thanks! | |
Aug 12, 2016 at 2:06 | vote | accept | Sávio | ||
Aug 12, 2016 at 1:58 | history | answered | user44191 | CC BY-SA 3.0 |