Timeline for Is $(pE(L))^{\operatorname{Gal}(L/K)}/pE(K)=0$ for almost all $p\geq 5$ if $rank(E)\geq 1$, where $L=K(E_{5^{\infty}7^{\infty}11^{\infty}...})$?
Current License: CC BY-SA 3.0
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| Aug 7, 2016 at 18:01 | comment | added | Chris Wuthrich | That looks like a stab in the dark to me. I can't see a reason why this quotient is finite for a single p, let alone trivial. The rank of E(L) is infinite, the quotient is a subgroup of $H^1(G, E[p])$ which is infinite dimensional, because G has many cyclic quotients of order p. | |
| Aug 7, 2016 at 15:32 | history | edited | The Thin Whistler | CC BY-SA 3.0 |
added 71 characters in body; edited title
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| Aug 7, 2016 at 11:35 | history | edited | The Thin Whistler | CC BY-SA 3.0 |
added 8 characters in body; edited title
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| Aug 7, 2016 at 11:06 | history | asked | The Thin Whistler | CC BY-SA 3.0 |