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Jan 13, 2019 at 8:24 comment added Alexander Chervov I feel it is quite similar to what we wrote extending Jacobi identity to matrices with non-commuting entries (Manin matrices) arxiv.org/abs/0901.0235
Jan 12, 2019 at 21:12 history edited darij grinberg CC BY-SA 4.0
improve latex, update ref, fix typos
Dec 19, 2017 at 19:54 comment added darij grinberg @PietroMajer: This is what I was trying to achieve when I started writing the proof. Unfortunately, it's not directly clear to me how this works.
Dec 19, 2017 at 18:48 comment added Pietro Majer So the functoriality of $\Lambda^k$ reads as the (generalized) Cauchy-Binet formula: en.wikipedia.org/wiki/Cauchy–Binet_formula#Generalization . In the same spirit, I'd like to see Theorem 1 as a statement on the inverse matrix of the linear map $\Lambda^k(f_A)$, or better, since it also refers to $\tilde I$ and $\tilde J$, of the linear map $\Lambda^k(f_A)^*\sim\Lambda^{n-k}(f_A)$. Can this produce a proof to Theorem 1 consisting in a plain translation of facts about exterior algebra in the language of matrices?
Dec 19, 2017 at 18:48 comment added Pietro Majer If we agree to see a $\mathbb{K}$-matrix as a function $S\times S\to\mathbb{K}$ , with any finite index set $S$ (not just some $[m]$), then, according to Proposition 3, the matrix of the linear map $\Lambda^k(f_B)$ in the basis $\{e_I\}_{I\in\mathcal{P}_k([n])}$ is $[\det(B^I_J)]_{(I\times J)\in\mathcal{P}_k([n])\times \mathcal{P}_k([n])}$.
Dec 23, 2016 at 22:40 history edited darij grinberg CC BY-SA 3.0
fix typos, update references
Aug 4, 2016 at 15:54 history edited darij grinberg CC BY-SA 3.0
corrections
Aug 4, 2016 at 15:47 history answered darij grinberg CC BY-SA 3.0