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May 14, 2010 at 17:58 history edited Qfwfq CC BY-SA 2.5
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May 14, 2010 at 17:50 comment added Qfwfq The equality I wrote above absolutely doesn't work! For example, if $G$ has positive dimension, the "expected" dimentions of the two sides do not match.
May 14, 2010 at 17:16 comment added user2035 $(G\times G)/G\not\cong(G/G)\times(G/G)$
May 14, 2010 at 17:07 comment added Qfwfq I mean, if $G$ acts on $X$ and $Y$, and diagonally on $X\times Y$, then $(X\times Y)/G\cong (X/G)\times (Y/G)$. Is it correct, right?
May 14, 2010 at 16:49 history edited Qfwfq CC BY-SA 2.5
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May 14, 2010 at 16:49 comment added S. Carnahan Your third isomorphism requires an identification between Sn and (Sn)^k.
May 14, 2010 at 16:32 history answered Qfwfq CC BY-SA 2.5