Skip to main content
11 events
when toggle format what by license comment
May 10, 2017 at 11:45 vote accept sampath
May 10, 2017 at 11:45
May 9, 2017 at 14:32 answer added Will Sawin timeline score: 3
May 9, 2017 at 14:12 comment added Will Sawin @sam Certainly not when $q$ is large with respect to $\ell$.
May 9, 2017 at 11:51 comment added sampath @WillSawin, Given $\ell$ and $\zeta$ does there exist $i,j$ with satisfying these equations ?
May 9, 2017 at 11:47 comment added sampath @LSpice, Thank you. What you stated is true.
May 9, 2017 at 2:23 comment added LSpice @KConrad, maybe norm 1 is implicitly referring to the elements $\zeta^{1 - q^i}$?
May 9, 2017 at 1:30 comment added Will Sawin I think it can be shown that for fixed $\ell, i,j$ the number of $\zeta$ satisfying these equations for $q$ large enough is $q^{\ell -2} + O( q^{ \ell - 5/2})$. So the total number of solutions is something like ${\ell -1 \choose 2} q^{\ell -2 } $.
May 9, 2017 at 1:09 comment added Will Sawin Clearly not when $\zeta \in \mathbb F_q$. Also usually not for $\ell$ small, presumably. Or do you mean does there exist some $\zeta$?
May 8, 2017 at 23:45 comment added KConrad The title of the questions mentions trace 0 and norm 1, but the question itself does not mention any norms.
May 8, 2017 at 23:22 history edited Gerry Myerson
edited tags
Aug 2, 2016 at 10:22 history asked sampath CC BY-SA 3.0