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Aug 1, 2016 at 17:46 comment added Nick Gill @UriBader, that's an interesting fact about infinite fields -- and one I should have known already! Thanks for filling in a gap in my knowledge.
Aug 1, 2016 at 9:03 vote accept Oliver
Aug 1, 2016 at 6:31 comment added Uri Bader @NickGill thanks for this correction. I put an answer based on it. Projective special linear and symplectic groups are always simple over infinite fields.
Aug 1, 2016 at 6:20 answer added Uri Bader timeline score: 5
Jul 31, 2016 at 23:50 comment added Nick Gill Note that if the field has characteristic $2$, then transvections are involutions so the answer is YES immediately (at least for finite fields -- I'm not sure about simplicity results for infinite fields).... In particular (with reference to the comments above) note that ${\rm SL}_2(2^a)$ is generated by involutions
Jul 31, 2016 at 15:31 history edited Oliver CC BY-SA 3.0
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Jul 31, 2016 at 13:27 review Suggested edits
Jul 31, 2016 at 14:01
Jul 31, 2016 at 12:51 comment added Uri Bader Just to justify my comment above and finish the discussion: $\text{Sp}(4)$ does contain a copy of $\text{GL}_2$ embedded by $A\mapsto$ a block diagonal matrix with $A$ and the transpose inverse of $A$ on the 2x2 diagonal blocks. Here the form is given by $I$ and $-I$ on the of-diagonal blocks.
Jul 31, 2016 at 12:32 comment added Uri Bader So the answer should be: no in dim=2 (but yes for the projective group) and yes in higher dimensions.
Jul 31, 2016 at 12:29 comment added Uri Bader Yes, I just noticed that. $\text{PSL}_2$ is generated by involution, but $\text{SL}_2$ does not, I was too quick to answer...
Jul 31, 2016 at 12:28 comment added Oliver I am not sure. In $SL_2$ the only nontrivial symplectic involution is $-1$.
Jul 31, 2016 at 12:18 comment added Uri Bader Note that on a two dimensional space the form $(a,c),(b,d)\mapsto ad-bc$ is just the determinant, so $\text{Sp}=\text{SL}$. Thus also in higher dimensions the symplectic group contains many copies of $\text{SL}_2$. In fact, it is generated by these (this, again, could be seen by simplicity, but in fact it holds in a complete generality (I think)).
Jul 31, 2016 at 12:06 comment added Oliver May I ask you to be more specific?
Jul 31, 2016 at 12:04 comment added Uri Bader Alternatively: use the fact that it is generated by $\text{SL}_2$'s.
Jul 31, 2016 at 11:56 comment added Uri Bader Note that the projective symplectic group is simple (unless you're in some very special cases, see below). In this case (clearly having a non-trivial involution) it must be generated by involutions, as these generate a normal subgroup. See groupprops.subwiki.org/wiki/…
Jul 31, 2016 at 11:53 history edited Oliver CC BY-SA 3.0
added 13 characters in body
Jul 31, 2016 at 11:52 comment added Uri Bader Is $b$ non-degenerate? What about $F=\mathbb{R}$, $V$ 1-dimensional, $b=0$?
Jul 31, 2016 at 11:21 history asked Oliver CC BY-SA 3.0