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Jul 30, 2016 at 19:37 vote accept sharpe
Jul 30, 2016 at 19:10 vote accept sharpe
Jul 30, 2016 at 19:37
Jul 30, 2016 at 17:24 answer added user95683 timeline score: 4
Jul 30, 2016 at 15:39 comment added sharpe If $\partial D$ is unbounded, I think it is difficult to deal with $d(x,\partial D)$. So I cut $\partial D$ by closed ball.
Jul 30, 2016 at 14:38 comment added ThiKu So you want $z$ and $r$ to be fixed? Why?
Jul 30, 2016 at 11:26 history edited sharpe CC BY-SA 3.0
added 4 characters in body
Jul 30, 2016 at 8:42 history asked sharpe CC BY-SA 3.0