Timeline for Is the Bott-Chern/Aeppli cohomology determined by the de Rham and Dolbeault cohomologies?
Current License: CC BY-SA 3.0
11 events
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Aug 3, 2016 at 8:25 | answer | added | daniele | timeline score: 9 | |
Aug 2, 2016 at 18:57 | history | edited | Michael Albanese | CC BY-SA 3.0 |
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Aug 2, 2016 at 1:04 | vote | accept | Andrew McHugh | ||
Aug 1, 2016 at 23:38 | history | edited | Michael Albanese | CC BY-SA 3.0 |
added 1 character in body; edited tags; edited title
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Aug 1, 2016 at 23:01 | answer | added | Michael Albanese | timeline score: 10 | |
Jul 31, 2016 at 15:56 | comment | added | Andrew McHugh | @MichaelAlbanese : If you would be so kind as to write up such an answer it would be appreciated. Thank you for your help. | |
Jul 30, 2016 at 18:46 | comment | added | Michael Albanese | @Andrew McHugh: I think it would be useful to have an outline of the example in an answer below. Would you mind writing up such an answer? If not, I can do it. | |
Jul 30, 2016 at 17:29 | comment | added | YangMills | An interesting question is whether this can happen already on compact complex surfaces. In all the cases, Bott-Chern/Aeppli is determined by DeRham and Dolbeault, except possibly for non-Kahler elliptic surfaces where in general the dimensions of Bott-Chern/Aeppli are not known. | |
Jul 30, 2016 at 16:27 | comment | added | Andrew McHugh | Thank you for the lead/hint. Angella does show an example of two different classes(which he calls iia and iib ) of deformations of the Iwasawa manifold in the table on p. 49 which have different Bott-Chern/Aeppli cohomology and the same DeRham and Dolbeault cohomologies. You've basically answered my question. | |
Jul 30, 2016 at 5:22 | comment | added | Michael Albanese | I don't know the answer, but I suggest looking in Angella's Cohomological Aspects in Complex non-Kähler Geometry. | |
Jul 30, 2016 at 5:03 | history | asked | Andrew McHugh | CC BY-SA 3.0 |