Timeline for Is the inverse of the criterion of fully-faithfulness of derived tensor product also true?
Current License: CC BY-SA 3.0
3 events
| when toggle format | what | by | license | comment | |
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| Jul 27, 2016 at 14:19 | comment | added | Zhaoting Wei | @DenisNardin Oh yes that's so obvious. Thank you. | |
| Jul 27, 2016 at 14:12 | comment | added | Denis Nardin | Isn't $H^i(A)=\mathrm{Hom}_{D(A)}(A,A[i])$, so the claim follows immediately from full faithfulness (without even the compactness of $N$)? | |
| Jul 27, 2016 at 13:54 | history | asked | Zhaoting Wei | CC BY-SA 3.0 |