Timeline for What did Yu Jianchun discover about Carmichael numbers?
Current License: CC BY-SA 3.0
5 events
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Jul 27, 2016 at 2:04 | comment | added | Ted Mao | Agree. A quote from a facebook friend of mine: "(to say that it is too short to publish in a paper) because its proof is homework-level. The result is that if $6k+1, 18k+1,54k^2+12k+1$ is prime, then their product $n$ is a Carmichael number. But one can prove this directly using Chinese remainder and little Fermat. Just need to show that $(n-1)$ is divisible by $6k, 18k, 54k^2+12k$." One can generate many similar criteria with a program. | |
Jul 27, 2016 at 1:45 | history | edited | Maksym Voznyy | CC BY-SA 3.0 |
added 51 characters in body
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Jul 26, 2016 at 15:41 | review | Low quality posts | |||
Jul 26, 2016 at 18:13 | |||||
Jul 26, 2016 at 15:20 | review | First posts | |||
Jul 26, 2016 at 15:51 | |||||
Jul 26, 2016 at 15:15 | history | answered | Maksym Voznyy | CC BY-SA 3.0 |