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Oct 4, 2016 at 8:26 vote accept DLIN
Jul 25, 2016 at 13:48 comment added Ben McKay Maybe it is easier to picture that the dimension of the $G$-orbit at a point $m \in M$ is the dimension of the set of vectors $v(m)$ for $v \in \mathfrak{g}$. This is in standard textbooks, like Abraham and Marsden. Pick as many vector fields $v_i \in \mathfrak{g}$ as you can which are linearly independent at $m$, and they remain so nearby.
Jul 25, 2016 at 13:38 answer added Friedrich Knop timeline score: 6
Jul 25, 2016 at 13:27 comment added DLIN I do not follow, the rank is no continuous. Why the rank of vanishing Lie algebra is zero nearby? Sorry@BenMcKay
Jul 25, 2016 at 13:23 comment added Ben McKay Local freedom is clear: look at the rank of elements of the Lie algebra vanishing at each point. Since the rank is zero along $N$, it is zero nearby.
Jul 25, 2016 at 12:48 history asked DLIN CC BY-SA 3.0