Timeline for An inequality of real continuous function with f'>0 and f''>0
Current License: CC BY-SA 3.0
5 events
when toggle format | what | by | license | comment | |
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Jul 25, 2016 at 3:03 | vote | accept | Oai Thanh Đào | ||
Jul 25, 2016 at 2:15 | comment | added | Iosif Pinelis | Yes, this will also do. | |
Jul 25, 2016 at 2:13 | comment | added | Nate Eldredge | Or to skip the convolution, take $n=3$, $m=x_1=0$, and $M=x_2=x_3=1$, and $f(x)=x^k$. Then the inequality reads $$\frac{2}{3} - \left(\frac{2}{3}\right)^k \le \frac{1}{2} - \left(\frac{1}{2}\right)^k$$ which is clearly false for large $k$. (Indeed, for $k \ge 4$.) | |
Jul 25, 2016 at 2:12 | history | edited | Iosif Pinelis | CC BY-SA 3.0 |
added 401 characters in body
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Jul 25, 2016 at 1:59 | history | answered | Iosif Pinelis | CC BY-SA 3.0 |