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In this postthis post it was proven that, except for a finite few, all zeros of $\Gamma(s) \pm \Gamma(1-s)$ are either real or reside on the line $\Re(s)=\frac12$.

I have been searching for similar reflexive $\pm$ $\Gamma$-functions that would not have a finite few exceptions and based on numerical evidence I like to conjecture that all zeros of:

$$\dfrac{\Gamma'}{\Gamma^2}(s) \pm \dfrac{\Gamma'}{\Gamma^2}(1-s)$$

or expressed differently with $\Psi(s)$ the Digamma function:

$$\dfrac{\Psi}{\Gamma}(s) \pm \dfrac{\Psi}{\Gamma}(1-s)$$

are either real or reside on the line with $\Re(s)=\frac12$.

Question:

Could this be proven using the techniques applied to $\Gamma(s) \pm \Gamma(1-s)$ ?

Just as a side observation:

A similar effect appears to occur for $\zeta(s) \pm \zeta(1-s)$$\zeta(s) \pm \zeta(1-s)$ that (assuming the RH) also induces a finite few complex zeros lying off the critical line and these also seem to be absent when using:

$$\dfrac{\zeta'}{\zeta}(s) \pm \dfrac{\zeta'}{\zeta}(1-s)$$

as framed up in this questionthis question.

In this post it was proven that, except for a finite few, all zeros of $\Gamma(s) \pm \Gamma(1-s)$ are either real or reside on the line $\Re(s)=\frac12$.

I have been searching for similar reflexive $\pm$ $\Gamma$-functions that would not have a finite few exceptions and based on numerical evidence I like to conjecture that all zeros of:

$$\dfrac{\Gamma'}{\Gamma^2}(s) \pm \dfrac{\Gamma'}{\Gamma^2}(1-s)$$

or expressed differently with $\Psi(s)$ the Digamma function:

$$\dfrac{\Psi}{\Gamma}(s) \pm \dfrac{\Psi}{\Gamma}(1-s)$$

are either real or reside on the line with $\Re(s)=\frac12$.

Question:

Could this be proven using the techniques applied to $\Gamma(s) \pm \Gamma(1-s)$ ?

Just as a side observation:

A similar effect appears to occur for $\zeta(s) \pm \zeta(1-s)$ that (assuming the RH) also induces a finite few complex zeros lying off the critical line and these also seem to be absent when using:

$$\dfrac{\zeta'}{\zeta}(s) \pm \dfrac{\zeta'}{\zeta}(1-s)$$

as framed up in this question.

In this post it was proven that, except for a finite few, all zeros of $\Gamma(s) \pm \Gamma(1-s)$ are either real or reside on the line $\Re(s)=\frac12$.

I have been searching for similar reflexive $\pm$ $\Gamma$-functions that would not have a finite few exceptions and based on numerical evidence I like to conjecture that all zeros of:

$$\dfrac{\Gamma'}{\Gamma^2}(s) \pm \dfrac{\Gamma'}{\Gamma^2}(1-s)$$

or expressed differently with $\Psi(s)$ the Digamma function:

$$\dfrac{\Psi}{\Gamma}(s) \pm \dfrac{\Psi}{\Gamma}(1-s)$$

are either real or reside on the line with $\Re(s)=\frac12$.

Question:

Could this be proven using the techniques applied to $\Gamma(s) \pm \Gamma(1-s)$ ?

Just as a side observation:

A similar effect appears to occur for $\zeta(s) \pm \zeta(1-s)$ that (assuming the RH) also induces a finite few complex zeros lying off the critical line and these also seem to be absent when using:

$$\dfrac{\zeta'}{\zeta}(s) \pm \dfrac{\zeta'}{\zeta}(1-s)$$

as framed up in this question.

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Agno
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Are all zeros of $\dfrac{\Gamma'}{\Gamma^2}(s) \pm \dfrac{\Gamma'}{\Gamma^2}(1-s)$ either real or on the line with $\Re(s)=\frac12$?

In this post it was proven that, except for a finite few, all zeros of $\Gamma(s) \pm \Gamma(1-s)$ are either real or reside on the line $\Re(s)=\frac12$.

I have been searching for similar reflexive $\pm$ $\Gamma$-functions that would not have a finite few exceptions and based on numerical evidence I like to conjecture that all zeros of:

$$\dfrac{\Gamma'}{\Gamma^2}(s) \pm \dfrac{\Gamma'}{\Gamma^2}(1-s)$$

or expressed differently with $\Psi(s)$ the Digamma function:

$$\dfrac{\Psi}{\Gamma}(s) \pm \dfrac{\Psi}{\Gamma}(1-s)$$

are either real or reside on the line with $\Re(s)=\frac12$.

Question:

Could this be proven using the techniques applied to $\Gamma(s) \pm \Gamma(1-s)$ ?

Just as a side observation:

A similar effect appears to occur for $\zeta(s) \pm \zeta(1-s)$ that (assuming the RH) also induces a finite few complex zeros lying off the critical line and these also seem to be absent when using:

$$\dfrac{\zeta'}{\zeta}(s) \pm \dfrac{\zeta'}{\zeta}(1-s)$$

as framed up in this question.