If $f\in\mathbf{C}[[q]]$ is non-constant, and algebraic over $\mathbf{C}[q]$ (in the sense that it is a root of a polynomial with coefficients in in $\mathbf{C}[q]$) then can $f$ be the $q$-expansion of a modular form (for some congruence subgroup of $SL(2,\mathbf{Z})$)?
I ask for the following reason. There are geometers in my department who occasionally come up with $q$-expansions (probably from counting things in geometry) and ask if these things are likely to be modular forms. Sometimes they are, sometimes they aren't, sometimes I don't know. But one that came up today I noticed was non-constant and algebraic over $\mathbf{C}[q]$ and so I instantly said that this should rule it out, and then I realised I could not immediately point to a proof of this.
Katz proved many years ago that a non-constant polynomial in $q$ can't be the $q$-expansion of a modular form but it's been a while since(by which I lookedmean a form which has no poles, even at the proofcusps), because if we have a non-constant polynomial modular form of some weight and I don't knowlevel, we can consider all modular forms of that weight and level which are polynomials in $q$, and then it's not hard to check that this space is Hecke stable, but Hecke operators tend to increase the degree of a polynomial modular form if it generaliseshas positive degree and it's not hard to finish the job now. I needSee Katz Antwerp III, p94 (p26 of the article).
Now I've found the time to go and do something elselook at the article, I realise that probably modular forms algebraic over $\mathbf{C}[q]$ might also form a Hecke-stable subspace, although now one can't use the degree trick to finish.
I was half-expecting the result to be false in characteristic $p$, but now I'm not so sure. I know that the $\Delta$ function is $\sum_{n\geq1,n\ \mathrm{odd}}q^{n^2}$ in a few hourscharacteristic 2 but presumably this isn't algebraic over $\mathbf{F}_2[q]$; I might come back and see what's happened torealise now that I have no good test for this question and add more if necessaryin my head.