Timeline for linear independence of $\sin(k \pi / m)$
Current License: CC BY-SA 3.0
4 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Jul 22, 2016 at 6:42 | comment | added | Fedor Petrov | by the way, multiplying by $\cos \frac\pi{18}$ we get Vladimir's example | |
| Jul 19, 2016 at 18:49 | comment | added | Fedor Petrov | @Nik at first, I started from 'almost counterexample' $2\sin\pi/6-\sin\pi/2=0$, which we all know from childhood. Then a natural idea to make a genuine counterexample is multiplying by some cosine and using $2\cos a\sin b=\sin(b+a)+\sin(b-a)$. Coprimality condition is easily examined. | |
| Jul 19, 2016 at 16:46 | comment | added | Nik Weaver | How do you come up with this? | |
| Jul 18, 2016 at 13:35 | history | answered | Fedor Petrov | CC BY-SA 3.0 |