Timeline for Without Choice: Are there filters of cardinality continuum?
Current License: CC BY-SA 3.0
6 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Jul 15, 2016 at 9:32 | comment | added | Asaf Karagila♦ | Well, I didn't really think about it in the context of choiceless mathematics. Which makes the whole story even weirder now. | |
| Jul 15, 2016 at 9:30 | vote | accept | Boaz Tsaban | ||
| Jul 15, 2016 at 9:30 | comment | added | Boaz Tsaban | We also arrived at this just now, in a seminar, and this was off the course of the seminar, just a curious question arising from a comment of Piotr Szweczak on selection principles. I never thought about math without choice before, so the coincidence is amazing. | |
| Jul 15, 2016 at 9:27 | comment | added | Boaz Tsaban | Blind spot on my side. Thanks for pointing this out. We indeed cared about filters on $\mathbb{N}$ as you wisely guessed. But I leave the question as is since you answered both possible interpretations. In short, your answer is that you can add all supersets of some coinfinite set (and you can add any coinfinite set you wish if all sets are cofinite). | |
| Jul 15, 2016 at 9:02 | comment | added | Asaf Karagila♦ | Oddly enough, I was thinking about the same question just two days ago. | |
| Jul 15, 2016 at 8:55 | history | answered | Asaf Karagila♦ | CC BY-SA 3.0 |