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Jul 19, 2016 at 9:33 vote accept Yashar Z
Jul 13, 2016 at 0:58 answer added Dima Pasechnik timeline score: 1
Jul 13, 2016 at 0:17 comment added Yashar Z Thanks for the quick reply. If I understood it right, using Farkas' Lemma one trades the original problem for its dual as now there is the problem of searching for $z$, and it doesn't seem searching/solving for $z$ is any easier than the original problem. I am missing something here?
Jul 12, 2016 at 22:58 review First posts
Jul 12, 2016 at 23:09
Jul 12, 2016 at 22:58 comment added David Handelman Farkas' Lemma (see the Wikipedia article) gives a little information; no solution exists iff there exists a row $z$ such that $zA \geq 0$ but $zy < 0$. It's not clear (to me) how this can be used to characterize the $x$.
Jul 12, 2016 at 22:51 history asked Yashar Z CC BY-SA 3.0