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May 12, 2010 at 19:28 vote accept CuriousUser
May 12, 2010 at 18:12 comment added Torsten Ekedahl See amendment to the answer.
May 12, 2010 at 18:11 history edited Torsten Ekedahl CC BY-SA 2.5
Answered the actual question.
May 12, 2010 at 17:41 comment added CuriousUser I'm sorry, I'm a bit confused: suppose we're in $T^2$, and $v=(1,1/2)$. Then $T_v=S^1$, but according to your formula i should get $\dim T_v=1-1=0$. Is there something I'm missing?
May 12, 2010 at 17:27 history answered Torsten Ekedahl CC BY-SA 2.5