Timeline for Are two conic bundles birational, if their bases are birational via a map preserving the associated quaternion algebras?
Current License: CC BY-SA 3.0
6 events
| when toggle format | what | by | license | comment | |
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| Jul 6, 2016 at 21:10 | comment | added | Bernie | @Jason: Thanks! This seems good. Since the birational map between the generic curves is induced by $\phi$, this birational map between the generic curves gives rise to the desired birational map between $C$ and $C'$. | |
| Jul 6, 2016 at 21:09 | comment | added | Bernie | @Francesco: Thanks. I shortened the title a bit, because I did not want it to be too long. Maybe it got shortened too much. I hope now it is not misleading. | |
| Jul 6, 2016 at 21:00 | history | edited | Bernie | CC BY-SA 3.0 |
Changed the misleading title
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| Jul 6, 2016 at 17:24 | comment | added | Jason Starr | If the birational transformation $X\dashrightarrow X'$ pulls back $a'$ to $a$, then the fibers of $C$, resp. $C'$, over the generic points of $X$, resp. $X'$ , are birational. | |
| Jul 6, 2016 at 13:47 | comment | added | Francesco Polizzi | The title of the question is misleading (as it is written, the answer is surely no). | |
| Jul 6, 2016 at 13:29 | history | asked | Bernie | CC BY-SA 3.0 |