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Jul 6, 2016 at 15:51 history bounty ended Dan Saattrup Nielsen
Jul 5, 2016 at 14:27 vote accept Dan Saattrup Nielsen
Jul 5, 2016 at 12:40 comment added Stefan Hoffelner Yes that's right
Jul 5, 2016 at 10:02 comment added Dan Saattrup Nielsen So, the reason why the extenders you mention are sufficient to capture all subsets of $V_\delta$ in the ultrapower is because $\text{lh }E$ is a cardinal of the ultrapower, so that any subset of $V_\delta$ lies in $\mathcal J_{\text{lh }E}^{\text{Ult}}$, which by coherence is just $\mathcal J_{\text{lh }E}^{\mathcal M}$, so we've already taken care of that subset. Is this correct?
Jul 5, 2016 at 9:36 history answered Stefan Hoffelner CC BY-SA 3.0