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Jul 3, 2016 at 21:33 answer added yakov timeline score: 2
Jul 3, 2016 at 16:41 comment added zibadawa timmy The condition implies that $C_G(M)=Z(M)$, and there are some results concerning $p$-groups that satisfy this for certain or all non-abelian subgroups. See this paper, for example. Those don't cover your specific (in some sense more general) question, though maybe it can lead you in good directions.
Jul 3, 2016 at 13:45 review Close votes
Jul 3, 2016 at 17:06
Jul 3, 2016 at 13:20 review First posts
Jul 3, 2016 at 13:27
Jul 3, 2016 at 13:19 history asked Maryam CC BY-SA 3.0