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Dec 3, 2019 at 12:49 comment added reuns Did you see anything on the zeros of the entire function $f(x)=\int_0^1 e^{-xt}t^{s-1}dt=x^{-s}\gamma(s,x)$, its Mellin transform being $\frac{\Gamma(z)}{z-s}$ this function has known-asymptotic on every ray from the origin, on $\Re(x) > 0$ it looks like $x^{-s}$ on $\Re(x)<0$ it looks like $e^{-x}$, thus the zeros get close to the imaginary axis where it is the Fourier transform of $t^{s-1}1_{t\in [0,1]}$
Mar 15, 2019 at 17:00 history edited Carlo Beenakker CC BY-SA 4.0
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May 1, 2017 at 21:45 comment added Carlo Beenakker A note on the real zeros of the incomplete gamma function, Ian Thompson
May 1, 2017 at 20:30 comment added Tom Copeland @CarloBeenakker, could you please give the title and author of your 2012 ref? I can't access the link. (Many links to papers become broken soon, so I'd suggest always providing the title and the author.)
Jun 29, 2016 at 21:45 comment added Carlo Beenakker the most recent paper I know of is from 2012 --- only asymptotics
Jun 29, 2016 at 21:33 comment added user40845 Thank you for the swift and detailed response. I'd looked at this resource a bit, it's how I found Franklin, and it has a wonderful description of the dynamics of the zeros. I was wondering though if any exact results had been derived for the structure of these trajectories, especially in the case $x=1$?
Jun 29, 2016 at 21:25 history edited Carlo Beenakker CC BY-SA 3.0
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Jun 29, 2016 at 21:17 history edited Carlo Beenakker CC BY-SA 3.0
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Jun 29, 2016 at 21:01 history answered Carlo Beenakker CC BY-SA 3.0