Timeline for Tail bound for product of normal distribution

9 events

when toggle format	what		by	license	comment
Aug 14, 2016 at 1:27	vote	accept	Wuchen
Jun 30, 2016 at 1:00	comment	added	Iosif Pinelis		As I said, the left tail of $X_b$ is the same as the right tail of $X_{−b}$ (not of $X_b$). Of course, the distribution of $X_b$ is not symmetric (about its mean).
Jun 30, 2016 at 0:32	history	edited	Iosif Pinelis	CC BY-SA 3.0	added 21 characters in body
Jun 30, 2016 at 0:27	comment	added	Wuchen		One more question, why is left tail the same as the right tail for $X_b$? It seems to me that $X_b$ is not symmetric around its mean.
Jun 30, 2016 at 0:18	comment	added	Wuchen		You are right, it works for all x. Thx!
Jun 29, 2016 at 23:42	comment	added	Iosif Pinelis		No further constraints on $x>b$. The condition $h_{b,x}\in(0,h_b)$ is automatically satisfied for all such $x$ and all $b\in(-1,1)$. I have added this detail to the answer.
Jun 29, 2016 at 23:18	comment	added	Wuchen		Thank you for your answer. This is exponential bound is true only when $h_{b,x} < h_{b}$, which poses constraints on $x$. Is that right?
Jun 29, 2016 at 21:19	history	edited	Iosif Pinelis	CC BY-SA 3.0	added 297 characters in body
Jun 29, 2016 at 19:41	history	answered	Iosif Pinelis	CC BY-SA 3.0