Timeline for Explicit construction of a bielliptic curve
Current License: CC BY-SA 3.0
3 events
| when toggle format | what | by | license | comment | |
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| Jun 29, 2016 at 8:59 | comment | added | rita | Since $\phi$ is a double cover, you have $K_C=\phi^*L$ for some $L\in Pic(E)$. It follows that $2P$ is (up to linear equivalence) a pull back from $E$. Since $h^0(C, 2P)=1$, the divisor $2P$ is invariant under the elliptic involution, so $P$ is a ramification point of $\phi$. Maybe this helps. | |
| Jun 28, 2016 at 15:43 | review | First posts | |||
| Jun 28, 2016 at 15:53 | |||||
| Jun 28, 2016 at 15:40 | history | asked | M. Jones | CC BY-SA 3.0 |