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Jun 27, 2016 at 7:59 answer added Uri Bader timeline score: 4
Jun 26, 2016 at 19:51 comment added PhoemueX As shown in this question (math.stackexchange.com/questions/1138259/…), two (finite) measures already agree if they agree on all balls of a fixed size. Thus, certainly in your case, they also agree.
Jun 25, 2016 at 21:43 vote accept Andreas Thom
Jun 25, 2016 at 21:43
Jun 25, 2016 at 18:35 comment added Uri Bader A guessed answer for the third question: for $f\in C_0(\mathbb{C})$, $\int fd\mu=\lim_{R\to\infty} \lim_{r \to 0} 1/(\pi r^2) \int_{|z|<R} \mu_z([0,r))f(z)$.
Jun 25, 2016 at 18:14 comment added Uri Bader $\mu_z([0,r))=\mu(B(z,r))$, so the answer to the first uestion is surely "yes".
Jun 25, 2016 at 17:50 answer added Christian Remling timeline score: 2
Jun 25, 2016 at 15:34 history asked Andreas Thom CC BY-SA 3.0