Timeline for Is $(G\rtimes H,H)$ a Gelfand pair iff $G$ is abelian?
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Sep 25 at 9:43 | comment | added | Tom WIlde | Another special case, where $|H|=p$ is prime, is studied in a paper of Fuma and Ninomiya. They give group theoretic equivalent conditions for $(GH,H)$ to be a Gelfand pair with $G$ nonabelian. In particular, $p$ must be a Fermat prime. | |
Jun 17, 2016 at 16:08 | history | edited | Geoff Robinson | CC BY-SA 3.0 |
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Jun 16, 2016 at 11:49 | history | answered | Geoff Robinson | CC BY-SA 3.0 |