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Oct 20, 2016 at 18:38 comment added Otis Chodosh @Thompson, The measures might converge but the associated varifolds do not converge as varifolds
Oct 20, 2016 at 18:17 comment added Thompson But the $\mathcal{H}^2$ measure of the graph is getting close to $2|B_1(0)|$. And more and more of it could have normal vector far from the normal to $P$. For example, isn't it fairly clear you can converge to $\sqrt{2}[P]$ by zig-zagging?
Jun 14, 2016 at 18:33 comment added Sam Thanks. Seems can use this argument to rule out any multiplicity 2 plane not perpendicular to P, for the perpendicular ones we need a gradient bound for the graphs to rule out that.
Jun 14, 2016 at 12:46 history answered Otis Chodosh CC BY-SA 3.0