Timeline for Is there an exponential map on (Hahn) ordered fields?
Current License: CC BY-SA 3.0
6 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Jun 14, 2016 at 23:14 | vote | accept | Twiffy | ||
| Jun 14, 2016 at 14:26 | answer | added | Philip Ehrlich | timeline score: 6 | |
| Jun 14, 2016 at 7:21 | comment | added | nombre | Can you explain how you would extend linearly? Also, please clarify the structure of $G$. Usuallly, additive notations are used for $G$, here you seem to be assuming it is a ring. | |
| Jun 14, 2016 at 6:35 | review | First posts | |||
| Jun 14, 2016 at 6:53 | |||||
| Jun 14, 2016 at 6:33 | comment | added | Twiffy | In case it's helpful, here's an example of an exponential map I was able to construct that does not fit the bill: $$ \textrm{exp}\left( r \cdot t^\eta \right) = e^r \cdot t^{r\eta} $$ where $t$ is the formal indeterminate. This definition is for a single-term Laurent series, but gets extended by linearity; we also take $\textrm{exp}(0) = 1$ of course. Notice in particular how this exponential map assumes that $F \subset G$; I suspect an exponential map that does fit the bill may require something similar. | |
| Jun 14, 2016 at 6:33 | history | asked | Twiffy | CC BY-SA 3.0 |