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Jan 6, 2023 at 10:57 history edited Martin Sleziak CC BY-SA 4.0
http -> https (the question was bumped anyway)
Dec 25, 2022 at 23:48 history edited YCor CC BY-SA 4.0
removed capitals from title
Jun 11, 2016 at 1:31 comment added Mark Lewko Ack, yes, you're right.
Jun 11, 2016 at 1:24 comment added Matt Rosenzweig @MarkLewko: If the $|e_{\alpha}-e_{\alpha'}|\sim 1/N$, then $T_{\alpha}$ $T_{\alpha'}$ intersect on the ball $B(0,N/2)$ and are contained in the ball $B(0,N/2)$. I don't see how your argument works. Am I misunderstanding you?
Jun 11, 2016 at 0:41 comment added Matt Rosenzweig @MarkLewko: Thank you for your comment. I edited my question to include the argument up with which I came. Is it what you had in mind?
Jun 11, 2016 at 0:37 history edited Matt Rosenzweig CC BY-SA 3.0
added 1731 characters in body; edited tags
Jun 10, 2016 at 23:23 history edited Willie Wong
edited tags
Jun 10, 2016 at 15:44 comment added Mark Lewko Try breaking the integrand on the left into two components. Component 1 should be a ball around the origin on which the tubes may overlap. Component 2 should be the set on which no two tubes overlap.
Jun 10, 2016 at 15:03 history edited Matt Rosenzweig CC BY-SA 3.0
Corrected exponents.
Jun 10, 2016 at 12:42 history asked Matt Rosenzweig CC BY-SA 3.0