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Jun 5, 2016 at 14:55 comment added Friedrich Knop That's correct. By the way, if $G$ is connected and compact and $M$ is compact then $\Theta=M$. This follows from Kirwan's connectedness theorem. Thus, $\Theta$ may be bigger than $\Sigma$.
Jun 5, 2016 at 14:19 comment added Olorin So we don't require, that the set $\Theta$ defined in my question, has to be an open and dense subset in $\Phi(M)$? It means only, that the set $N = \{ x \in M \ | \ \Phi(x) \in \Theta\}$ has to be open and dense in $M$, because that's "exactly" the set of points, such that the orbits through this points are coisotropic (modulo some critical points)?
Jun 5, 2016 at 13:55 history answered Friedrich Knop CC BY-SA 3.0