Timeline for Hasse principle for rational times square
Current License: CC BY-SA 3.0
11 events
when toggle format | what | by | license | comment | |
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Jun 16, 2016 at 4:52 | answer | added | Mikhail Borovoi | timeline score: 4 | |
Jun 14, 2016 at 18:22 | vote | accept | JadeSnail | ||
Jun 14, 2016 at 2:31 | answer | added | David E Speyer | timeline score: 7 | |
Jun 5, 2016 at 0:15 | answer | added | David E Speyer | timeline score: 13 | |
Jun 4, 2016 at 19:31 | answer | added | user42024 | timeline score: 8 | |
Jun 4, 2016 at 18:10 | comment | added | Mikhail Borovoi | (cont.). Let $\mathbb{L}$ denote the normal closure of $\mathbb{K}$ in $\overline{\mathbb{Q}}$, and let $G=\mathrm{Gal}(\mathbb{L}/\mathbb{Q})$. If all the Sylow subgroups of $G$ are cyclic, then the answer seem to be YES. In general I would expect the answer NO. | |
Jun 4, 2016 at 18:02 | comment | added | Mikhail Borovoi | Consider the question in the form of GH from MO. The answer seem to depend on $\mathbb{K}$. | |
Jun 4, 2016 at 16:01 | comment | added | GH from MO | Concerning the edit, the necessary condition needs to be strengthened as a whole (not just at the real places of $\mathbb{K}$): for any place $u$ of $\mathbb{Q}$, there is $q\in\mathbb{Q}$ such that for any place $v$ of $\mathbb{K}$ lying above $u$, we have $a=qk^2$ for some $k\in\mathbb{K}_v$. In fact the assumption $q\in\mathbb{Q}$ could be relaxed to the more natural condition $q\in\mathbb{Q}_u$. | |
Jun 4, 2016 at 15:24 | history | edited | Mikhail Borovoi |
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Jun 4, 2016 at 15:02 | history | edited | JadeSnail | CC BY-SA 3.0 |
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Jun 4, 2016 at 14:20 | history | asked | JadeSnail | CC BY-SA 3.0 |