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S Jun 8, 2016 at 8:00 history bounty ended Lisa S.
S Jun 8, 2016 at 8:00 history notice removed Lisa S.
Jun 7, 2016 at 19:22 vote accept Lisa S.
Jun 7, 2016 at 15:44 answer added Oli Gregory timeline score: 2
Jun 7, 2016 at 15:08 comment added Lisa S. @OliGregory: Thanks! You should post this as an answer: as far as I can tell the reference you give resolves the question.
Jun 7, 2016 at 8:29 comment added Oli Gregory Perhaps you already know this, but page 11, proposition 3 (and the subsequent sub-lemmas) of Zink's "The display of a formal $p$-divisible group" looks relevant. Here's the address of the paper on his website... math.uni-bielefeld.de/~zink/display.pdf
S Jun 7, 2016 at 6:23 history bounty started Lisa S.
S Jun 7, 2016 at 6:23 history notice added Lisa S. Draw attention
Jun 4, 2016 at 13:17 comment added YCor @znt if $G$ is a compact abelian group such that for all $x$, $p^nx\to 0$ when $n\to\infty$ and $G$ torsion-free, then $G$ is isomorphic to some power of $\mathbf{Z}_p$. This is easy to establish with Pontryagin duality (because the Pontryagin dual is a discrete, divisible abelian group in which every element is killed by some power of $p$, hence is a direct sum of copies of $\mathbf{Z}[1/p]/\mathbf{Z}$).
Jun 4, 2016 at 12:18 comment added znt I believe that the p-Witt vectors for $\mathbf{Z}_p$ is isomorphic, as an abelian group, to a product of countably infinitely many copies of $\mathbf{Z}_p$ (I believe this because if memory serves then Hendrik Lenstra told me this in 2002, and if it's wrong then it's my memory at fault), and the p-Witt vectors for $\mathbf{Z}/p^m$ is isomorphic as an abelian group to a product of $\mathbf{Z}_p$ and countably infinitely many copies of $\mathbf{Z}/p^{m-1}$ (with the same reference and caveat). So there are least are some examples when it's true.
Jun 4, 2016 at 10:46 history asked Lisa S. CC BY-SA 3.0