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Nov 21, 2018 at 3:20 comment added HenrikRüping @MadHatter: The $T_i$'s form a decreasing sequence of open sets, Thus their union is just the first of the $T_i$'s, if we replaced union by intersection, we dont get something open. It also follows that if any basic open neighborhood of 0 is contained in only finitely many of the $S_i$'s, then any open nbhd of 0 can be contained in finitely many of the $S_i$'s (just pick a basic open nbh contained in it).
Nov 20, 2018 at 22:03 comment added Rafał Gruszczyński Henrik, the third paragraph should say "any basic open neighborhood of 0", for if you take for example $T_n$ to be the set of all sequences which have 0's at first $n$ terms, than $\bigcup_{n\in\omega}T_n$ is cotained in every $S_i$, for $i\in\omega$. Am I right?
Aug 31, 2016 at 12:08 vote accept Rafał Gruszczyński
Jun 3, 2016 at 11:03 history answered HenrikRüping CC BY-SA 3.0