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Jun 2, 2016 at 7:12 answer added Fedor Petrov timeline score: 2
Jun 2, 2016 at 7:00 comment added Danny Nguyen Yes. This is true. The polynomial $P$ must contain many monomials however.
Jun 2, 2016 at 6:56 comment added Qiaochu Yuan $A_k$ is a finite union of arithmetic progressions with common difference $p_1 \dots p_k$, so the generating function has the form $\frac{P(x)}{1 - x^{p_1 \dots p_k}}$ for some polynomial $P(x)$. The computation of $P(x)$ is exactly the computation of the first $p_1 \dots p_k$ terms of the sequence. I don't know if that's the sort of answer you're looking for.
Jun 2, 2016 at 6:50 history asked Danny Nguyen CC BY-SA 3.0