Timeline for Number of prime divisors of p^2-1 for a prime p
Current License: CC BY-SA 3.0
5 events
when toggle format | what | by | license | comment | |
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May 25, 2016 at 16:35 | comment | added | Terry Tao | Actually the discussion on page 2 of the Maynard paper in my previous comment suggests that one can take k=11 for the original problem. | |
May 25, 2016 at 16:28 | comment | added | Terry Tao | As $p^2-1$ is going to be divisible by 24 for large $p$, one should reduce $k$ by $4$ and work with $(p+1)(p-1)/24$. In view of arxiv.org/abs/1205.5021 it might be possible to get $k$ down to 6+4=10 with current methods, though in that paper one cannot specify one of the three linear forms $L_1(n), L_2(n), L_3(n)$ to be prime, so probably one has to make do with something slightly worse than 10. In any event Maynard's result certainly shows that $\Omega(n(n^2-1)) \leq 11$ infinitely often, with $n$ coprime to any fixed finite number of primes. | |
May 25, 2016 at 15:27 | comment | added | Lucia | Any sieve method will show this for some value of $k$ -- e.g. $k=20$ would probably be pretty easy to show (and probably something like $k=10$ would be known with some effort). | |
May 25, 2016 at 11:51 | answer | added | joro | timeline score: 3 | |
May 25, 2016 at 8:46 | history | asked | Buturlakin Alexander | CC BY-SA 3.0 |