Timeline for Converge of measures [closed]
Current License: CC BY-SA 3.0
6 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| May 25, 2016 at 19:21 | comment | added | Rusbert | If, misspelling, I meant $(Y,d)$. | |
| May 25, 2016 at 6:37 | history | closed |
Nik Weaver Neil Hoffman Peter Humphries Stefan Waldmann András Bátkai |
Not suitable for this site | |
| May 25, 2016 at 5:01 | comment | added | Martin Sleziak | You start your post with $(X,d)$, but $X$ is never mentioned again in your post, only $Y$. Typo, perhaps? | |
| May 25, 2016 at 4:11 | review | Close votes | |||
| May 25, 2016 at 6:37 | |||||
| May 25, 2016 at 3:56 | comment | added | Nik Weaver | It's not a research question. If $f$ is any discontinuous function then there exists a sequence $(x_n)$ in $X$ such that $x_n \to x \in X$ but $f(x_n) \not\to f(x)$. Letting $\mu_{x_n}$ be the Dirac measure at $x_n$, we then have $\mu_{x_n} \to \mu_x$ weak* (although I am not sure this term is appropriate) but $\int f\, d\mu_{x_n} \not\to \int f\, d\mu_x$. | |
| May 25, 2016 at 3:36 | history | asked | Rusbert | CC BY-SA 3.0 |