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May 25, 2016 at 1:02 history edited GH from MO
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May 25, 2016 at 0:12 vote accept DiophantineStudy
May 25, 2016 at 0:12
May 24, 2016 at 22:53 answer added Gerry Myerson timeline score: 3
May 24, 2016 at 22:11 answer added Lucia timeline score: 13
May 24, 2016 at 21:43 history edited DiophantineStudy CC BY-SA 3.0
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May 24, 2016 at 21:34 comment added DiophantineStudy Thanks, very nice a special solution. I have edited my questions, should be $a^2+b^2=c^2+d^2+n$ for any integer n.
May 24, 2016 at 21:33 history edited DiophantineStudy CC BY-SA 3.0
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May 24, 2016 at 21:30 comment added Jarek Kuben For any $n\in\mathbb{Z}$ the 4-tuples $(n\pm1,n\mp1,n,n)$ are a solution, so there are obviously infinitely many for this one (not sure what you mean by "like").
May 24, 2016 at 21:21 history edited Wojowu CC BY-SA 3.0
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May 24, 2016 at 21:15 review First posts
May 24, 2016 at 21:21
May 24, 2016 at 21:15 comment added Wojowu You are essentially looking at numbers in this sequence at distance of 2 from each other.
May 24, 2016 at 21:11 history asked DiophantineStudy CC BY-SA 3.0