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Bill Johnson pointed out to me yesterdayyesterday that the map $$f \mapsto f^+ = \max(f,0)$$ is not weak* continuous on $l^\infty$. Nonetheless, I think I can prove that if $V$ is a linear subspace of $l^\infty$ which is stable under this operation, then its weak* closure is too. In other words, the weak* closure of any vector lattice in $l^\infty$ is a vector lattice. The proof is by transfinite induction! Does anyone know an easier proof of this simple fact?

Bill Johnson pointed out to me yesterday that the map $$f \mapsto f^+ = \max(f,0)$$ is not weak* continuous on $l^\infty$. Nonetheless, I think I can prove that if $V$ is a linear subspace of $l^\infty$ which is stable under this operation, then its weak* closure is too. In other words, the weak* closure of any vector lattice in $l^\infty$ is a vector lattice. The proof is by transfinite induction! Does anyone know an easier proof of this simple fact?

Bill Johnson pointed out to me yesterday that the map $$f \mapsto f^+ = \max(f,0)$$ is not weak* continuous on $l^\infty$. Nonetheless, I think I can prove that if $V$ is a linear subspace of $l^\infty$ which is stable under this operation, then its weak* closure is too. In other words, the weak* closure of any vector lattice in $l^\infty$ is a vector lattice. The proof is by transfinite induction! Does anyone know an easier proof of this simple fact?

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Nik Weaver
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Weak* continuity of positive parts, again

Bill Johnson pointed out to me yesterday that the map $$f \mapsto f^+ = \max(f,0)$$ is not weak* continuous on $l^\infty$. Nonetheless, I think I can prove that if $V$ is a linear subspace of $l^\infty$ which is stable under this operation, then its weak* closure is too. In other words, the weak* closure of any vector lattice in $l^\infty$ is a vector lattice. The proof is by transfinite induction! Does anyone know an easier proof of this simple fact?