Timeline for Derivation of a stochastic Navier-Stokes equation under the assumption of perturbed particle trajectories
Current License: CC BY-SA 3.0
13 events
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| Apr 13, 2017 at 12:19 | history | edited | CommunityBot |
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| S May 29, 2016 at 21:40 | history | bounty ended | CommunityBot | ||
| S May 29, 2016 at 21:40 | history | notice removed | CommunityBot | ||
| May 22, 2016 at 10:05 | comment | added | 0xbadf00d | @MichaelBächtold No, there should be no big $X$. I've intended to write that $(1)$ is simply $$\Phi_t(x_0)=\Phi_0(x_0)+\int_0^tv_t(x_0)\;{\rm d}t.$$ I've deleted my previous comment in order to prevent confusion. | |
| May 22, 2016 at 9:34 | comment | added | Michael Bächtold | I guess you are only considering time as independent variable, while the initial position $x_0$ is considered constant in that equation. You can do that, while I was considering space coordinates also as independent variables. Btw is there a difference between big X and small x in your previous eq? | |
| May 22, 2016 at 9:17 | comment | added | 0xbadf00d | @MichaelBächtold Sorry, I don't understand what you mean. $(1)$ is simply $$\Phi_t(X_0)=\Phi_0(X_0)+\int_0^tv_t(x_0)\;{\rm d}t.$$ | |
| May 22, 2016 at 9:12 | comment | added | Michael Bächtold | In eq (1) you are using differentials, but shouldn't the right hand side then also contain the additional terms with $dx_i$ wher the $x_i$ are coordinates on the initial configuration? I don't know if this is relevant to your problem since I'm not familiar with SPDEs, but it seems strange from the classical perspective. | |
| S May 21, 2016 at 20:38 | history | bounty started | 0xbadf00d | ||
| S May 21, 2016 at 20:38 | history | notice added | 0xbadf00d | Canonical answer required | |
| May 19, 2016 at 14:02 | history | edited | 0xbadf00d | CC BY-SA 3.0 |
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| May 19, 2016 at 13:54 | history | edited | 0xbadf00d | CC BY-SA 3.0 |
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| May 19, 2016 at 13:00 | review | First posts | |||
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| May 19, 2016 at 12:58 | history | asked | 0xbadf00d | CC BY-SA 3.0 |