Timeline for Ramanujan-type sum
Current License: CC BY-SA 3.0
6 events
| when toggle format | what | by | license | comment | |
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| Apr 13, 2017 at 12:58 | history | edited | CommunityBot |
replaced http://mathoverflow.net/ with https://mathoverflow.net/
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| Apr 13, 2017 at 12:19 | history | edited | CommunityBot |
replaced http://math.stackexchange.com/ with https://math.stackexchange.com/
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| May 18, 2016 at 6:55 | history | edited | Zurab Silagadze | CC BY-SA 3.0 |
right half ---> right-half
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| May 18, 2016 at 6:34 | history | edited | Zurab Silagadze | CC BY-SA 3.0 |
Some links and explanation added
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| May 17, 2016 at 21:18 | comment | added | antonio asis | Dear Mr Zurab good explanation but this integral it is difficul to resolve anyway the second sum it is possible calculate as $$\sum _{k=1}^{\infty } \frac{k}{1-e^{\frac{\pi k}{2}}}=\frac{6 \psi _{e^{4 \pi }}^{(1)}(1)+6 \psi _{e^{4 \pi }}^{(1)}\left(1-\frac{i}{4}\right)-\pi ^2-48 \pi }{24 \pi ^2}-\frac{2}{3}+\frac{1}{\pi }$$ | |
| May 17, 2016 at 13:26 | history | answered | Zurab Silagadze | CC BY-SA 3.0 |